Mark M. answered 02/05/23
Retired college math professor. Extensive tutoring experience.
3x2 - 2x + 4 = 0
x2 - (2/3)x = -4/3 [(1/2)(-2/3)]2 = 1/9
x2 - (2/3)x + 1/9 = -4/3 + 1/9
(x - 1/3)2 = -11/9
x - 1/3 = ± √(-11/9)
x = (1 ± √11 i) / 3
Amelia B.
asked 02/05/23Mark M. answered 02/05/23
Retired college math professor. Extensive tutoring experience.
3x2 - 2x + 4 = 0
x2 - (2/3)x = -4/3 [(1/2)(-2/3)]2 = 1/9
x2 - (2/3)x + 1/9 = -4/3 + 1/9
(x - 1/3)2 = -11/9
x - 1/3 = ± √(-11/9)
x = (1 ± √11 i) / 3
Vignesh N. answered 02/05/23
Math Tutor: Expert in Calculus, Linear Algebra, & Numerical Methods
3x2 - 2x + 4 = 0 (rearrange the given eqn to this form)
x = (2 +/-sqrt(4 - 4*3*4)) / (2*3) (use the formula to solve for the roots of the quadratic eqn)
x = (1 +/-sqrt(-11))/3 (x has imaginary roots)
x = (1 +/-sqrt(11)*i)/3 (i is the imaginary number sqrt(-1))
hope this helps
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