
Dayv O. answered 02/03/23
Attentive Reliable Knowledgeable Math Tutor
the thing is Andre is claiming log10(55)=1.5
which is wrong
and claiming the reason is f(x)=log10(x) is linear
which is wrong
the linear function 1/90=(y-1)/(x-10)
y=(x/90)+80/90
has solution x=55, y=1.5
log10(55) is not 1.5
the only two points where the linear equation is accurate
are at x=1 and x=2, the precise points picked
to create the line.
y=log10(x) is a curve not a line.
at x=o the curve goes toward negative infinity
to find log(x/2) use log(x/2)=logx-log2, and learn what log10(2) is. for log base 10, log10(2)=.3,,,for natural base e, ln2=.69.,,,,so log10(50)=2-.3=1.7,,,,,if I know ln(20.1)=3 then ln(10.05)=3-.69=2.31
Lorena T.
I'm more confused now. I'm still not sure how you determine halfway values for log functions. I know it is not the same for a linear function.02/03/23