Daniel B. answered 01/30/23
A retired computer professional to teach math, physics
The Rational Root Theorem statates that every rational root must be of the form
p/q, where
p must divide the constant term 2, and
q must divide the high order term 6.
So all the possible candidates for p are 2, 1, -1, -2, and
all the possible candidates for q are 6, 3, 2, 1, -1, -2, -3, -6.
Those would allow for 32 possible roots, but many combinations are equivalent.
We can ignore all the negative divisors and then add the opposite to each positive candidate for a root.
There are 6 positive candidates for a rational root.
2/6 = 1/3
1/6
2/3
2/2 = 1/1
1/2
2/1