How to graph f(x)=-5/3|x+4|

Question

f(x)=-5/3|x+4|

Answer 1

corrected, had problem as |x-4| vs. |x+4|

|x+4|=(x+4) when (x+4)>0,,,,,x>-4

so for x>-4, f(x)=(-5/3)(x+4)=(-5/3)x-20/3

|x+4|=-(x+4)=(-x-4) when (x+4)<0,,,,x<-4

so for x<-4 f(x)=(-5/3)(-x-4)=(5/3)x+20/3

x=-4 f(x)=0

Answer 2

Since the slope is -5/3:

1. the function has a V-shape downward
2. -5/3: it is a narrow V-shape to the y-axis