The length of a rectangle is 3 cm more than twice the width. If the area of the rectangle is 44cm . What is the width?

Answer 1

The formula for the area of a rectangle is A = W * L, where W is the width and L is the length. First define each of these terms.

The question gives us the expression that defines L: 3 cm more than twice the width, which means that

L = 2W + 3.

From there, substitute the expressions back into the area formula, where the area is 44 cm, and solve.

A = W * L = W * (2W + 3) = 44

Distribute the equation.

W(2W +3) = 44

2W² + 3W - 44 = 0

Then use the quadratic formula to solve for W.

W = (-b ± √(b² - 4ac)) / (2a)

= -((3) ± √(3² - 4(2)(-44))) / (2(2))

= (-3 ± √(9 + 352)) / (4)

= (-3 ± √(361)) / (4)

= (-3 ± 19) / (4)

Then solve for both signs.

W = (-3 - 19) / 4 = -22 / 4 = -5.5 cm OR W = (-3 + 19) / 4 = 16 / 4 = 4 cm

As negative width cannot exist, W = 4cm.

Answer 2

Let x = width. Then length = 2x + 3 The area is 44 cm²

So, x(2x + 3) = 44

Solve for x.

Answer 3

44 = w(2w + 3)

Can you solve for w and answer?