What is the standard form of an equation of the line that passes through the points 6,1 and 5,4

Question

6,1 and 5,4 standard form

Answer 1

Start with two-point form

(y - 1) / (x - 6) = (4 - 1) / (5 - 6)

Answer 2

let (6,1) = (x_1, y₁)

and (5,4) = (x_2, y₂)

find gradient: m = change in y/ change in x

then use (y - y₁) = m*(x -x₁)

Solve for y to get in standard form. You can show us your answer and we can check it. (surely you don't want us to do all the work... :) )