
Halston B.
asked 01/13/23The perimeter of the rectangular playing field is 404 yards no. The length of the field is 3 yards less than quadruple the width. what are the demonsions of the playing field?
this is as far as i got.
2x+2y=404
y=4x-3
2x+2(4x-3)=404
10x=404
what do i do from there?
1 Expert Answer
Raymond B. answered 01/13/23
Math, microeconomics or criminal justice
2L + 2W = 404
L +W = 202
L= 4W-3
4W-3 +W =202
5W= 205
W = 41 yards Wide
L =202-41 = 161 yards Long
L=4(41)-3 =164-3 = 161
dimensions are 41 by 161 yards
Your last line is off a little. Perfect until then.
It should Not be 10x -6 =404
then 10x =404+6 =410
then x =410/10 = 41 yards wide
you forgot to multiply the 2 by -3 = -6, then add 6 to 404
Still looking for help? Get the right answer, fast.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Peter R.
01/13/23