Solo D.
asked 01/10/23Evaluate 2 Problems and Demonstrate.
- 13C7
- 9P4
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1 Expert Answer
Yefim S. answered 01/11/23
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5
(20)
Math Tutor with Experience
13C7 = 13!/(7!·6!) = 13·12·11·10·9·8/(6·5·4·3·2·1) = 1716
9P4 = 9!/(5!) = 9·8·7·6 = 3024
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Mark M.
Have you located the formulas for these?01/10/23