Maximum You are given N number of inputs. Print the maximum of them after each input.

Question

Maximum You are given N number of inputs. Print the maximum of them after each input.

Explanation In the example, you are given 6 inputs 1, 0, 3, 2, 9, 8

1 is maximum in the input 1.

1 is maximum in the input 1, 0.

3 is maximum in the input 1, 0, 3.

3 is maximum in the input 1, 0, 3, 2.

9 is maximum in the input 1, 0, 3, 2, 9.

9 is maximum in the input 1, 0, 3, 2, 9,

so,the output should be

1

3

3

9

9

Answer 1

This program shows how to calculate the max in a list using the very useful reduce fn. from functools

No Python programmer should be without it, and its cousins, filter and map

It also shows how to use a lambda function, again something that every Pythonista should know.

The program below will work for any list (just change list in main()), and also demonstrates industry-standard code for writing Python applications

from functools import reduce

def max_in_list(li): # uses lambda function and reduce (list to single value)

return reduce(lambda a, b: a if a > b else b, li)

def run_max_tests(lst):

print('............. beginning test on max_in_list...................')

max_values = []

for i in range(1, len(lst) + 1):

slice = lst[:i] # a slice of the first i values in the list

# get max for slice, save in max_values list

max_values.append(max_in_list(slice))

# uses Python f-Strings, lst[-1] is its last value

print(f'{max_values[-1]} == max of {slice}')

print('-' * 10)

for el in max_values: # print out again, one value at a time w/o list

print(el)

print('................. ending test on max_in_list..................\n')

def main():

lst = [1, 0, 3, 2, 9, 8]

run_max_tests(lst=lst)

if __name__ == '__main__':

main()

# ===================================================================

# OUTPUT

# ===================================================================

# .................. beginning test on max_in_list...................

# 1 == max of [1]

# 1 == max of [1, 0]

# 3 == max of [1, 0, 3]

# 3 == max of [1, 0, 3, 2]

# 9 == max of [1, 0, 3, 2, 9]

# 9 == max of [1, 0, 3, 2, 9, 8]

# ----------

# 1

# 1

# 3

# 3

# 9

# 9

# ...................... ending test on max_in_list..................

Answer 2

The easiest way to accomplish this is to store the current max value in a variable (max_val, for instance). So, let's say that this is part of a loop; in other words, each input occurs during a new loop iteration. You can create the max_val variable before you start the loop and set it equal to 0. That way, when you start the loop, the first input value will be either greater than or equal to the max_val variable. Then, you just check which of the two values (max_val or the current input) is greater using an if function. If the current input is greater than max_val, then set max_val equal to the current input.

This is how it would go with your example (using shorthand):

max_val = 0 #an alternative could be setting it to some arbitrarily small number like -1000 as well

start loop

1st loop iteration: input = 1

is input (1) greater than max_val (0)?

Yes - set max_val = input #now max_val = 1

print(max_val)

1

2nd loop iteration: input = 0

is input (0) greater than max_val (1)?

No - do nothing.

print(max_val)

1

3rd loop iteration: input = 3

is input (3) greater than max_val (1)?

Yes - set max_val = input #now max_val = 3

print(max_val)

3

etc...