Solve: 3x^0 - 4x (-1 - 3^0) = 5(x + 3)

Answer 1

Assuming you wrote the problem correctly:

3x⁰ - 4x(-1 - 3⁰) = 5(x+3)

Any number raised to the power zero equals one (1). So, the equation becomes:

3·1 - 4x(-1 - 1) = 5(x+3)

3 - 4x(-2) = 5x + 15

3 + 8x = 5x + 15

Solve for x.

Answer 2

3x^0 -4x(-1-3^0) = 5(x+3)

= 3(1) -4x(-1-1) = 5x+15

= 3 -4x(-2) = 5x +15

= 3+8x =5x + 15

3x = 12

x = 4

any number or variable raised to the 0 power = 1

PEMDAS order of operations means -3^0 = -1, not (-1)^0= 1