Mark and Amy live 560 miles apart. They plan to meet in the middle. If Mark travels 20 mph and Amy travels at 50 mph and they leave at the same time how far will Mark travel before they meet.

Answer 1

m= 20, a =50

560 miles total

20+50 = 70

560/70 = 56/7 = 8 hours until they meet

20 mph times 8 = 160

50 mph times 8 = 400

160+ 400 = 560 miles

Answer 2

If they really do meet in the middle they'll both travel 560/2 = 280 miles!

However, if the question is how far M travels before the meet, can do the following:

D_m + A_m = 560

D = rt They're both on the road for the same length of time since they leave at the same time.

20t + 50t = 560

70t = 560. t = 8 hours

M will travel 20(8) = 160 mi.

A will travel 50(8) = 400 mi. Total 560 mi. No, they won't meet in the middle!