Inactive Tutor answered 12/09/22
We need 0 < 0.0071d³ – 0.090d² + 0.48d = (0.0071d² – 0.090d + 0.48)d = 0.0071(d² – (900/71)d + 4800/71)d = 0.0071((d – 450/71)² + 138300/5041)d which is always the case if d > 0.
Taylor S.
asked 12/09/22The weight of an ideal cut round diamond can be modeled by f(d)=o.0071d^3-0.090d^2+0.48d
where d is the diameter of the diamond. find the domain of the function in context of the situation
possible answers
A) the domain is all real numbers
B) the domain is {d|d>0}
c) the domain is {d|d<0}
D) the domain is {d|d>0.48}
Inactive Tutor answered 12/09/22
We need 0 < 0.0071d³ – 0.090d² + 0.48d = (0.0071d² – 0.090d + 0.48)d = 0.0071(d² – (900/71)d + 4800/71)d = 0.0071((d – 450/71)² + 138300/5041)d which is always the case if d > 0.
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