If you are given the location of the vertex, use the vertex form:
f(x) = a·(x-h)2 + k
where a is a constant and (h,k) is the location of the vertex. In your case (h,k) = (4,3), so:
f(x) = a·(x-4)2 + 3
For f(x+2), replace x with x+2:
f(x+2) = a·(x+2-4)2 + 3
f(x+2) = a·(x-2)2 + 3
What are the h and k values for f(x+2)?