If f(x) is an exponential function where f (1) = 11 and f(6.5) = 100, then find the value of f(12), to the nearest hundredth

Answer 1

11 = ab

100 = ab^6.5

0.9090 = b^5.5

ln 0.9090 = 5.5 ln b

-0.0954 = 5.5 ln b

-0.0173 = ln b

0.9828 = b

11 = 0.9828a

11.1925 = a

N = 11.1925(0.9828)¹²