Let f ( x ) = ( x + 5 ) 2 Find a domain on which f is one-to-one and non-decreasing.

Answer 1

The graph of f(x) = (x+5)² is a parabola opening upward with vertex at (-5, 0)

If we restrict the domain to (-5, ∞), we get a one-to-one function that is non-decreasing.

Answer 2

f(x) = (x + 5)²

Vertex at (-5, 0)

f is increasing and one to one for x ≥ -5