solve -6x^2-3x-2=0

Question

solve using the quadratic formula

Answer 1

The quadratic formula is:

So, in your case, a = -6, b = -3, and c = -2 so just plug these values into the formula:

x = [-(-3) ± √((-3)² - 4(-6)(-2))]/(2(-6))

x = [3 ± √(9 - 48)]/(-12)

x = (3 ± √-39)/-12