Mark M. answered 03/19/15
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
1 + tan2 (x) = sec2(x), so sec2(x) - 1 = tan2(x)
Therefore, sin2(x)/[sec2(x) - 1] = sin2(x)/tan2(x)
= sin2(x) ÷ [sin2(x)/cos2(x)]
= sin2(x) · [cos2(x)/sin2(x)]
= cos2(x)
Erica W.
03/19/15