Write an equation for a parabola with x-intercepts (-3,0) and (2,0) which passes through the point (1,-12)

Question

Write an equation for a parabola with x-intercepts (-3,0) and (2,0) which passes through the point (1,-12)

Answer 1

y = a(x - (-3))(x - 2) = a(x + 3)(x - 2)

Since the point (1, -12) is on the graph, -12 = a(1 + 3)(1 - 2). So, a = 3.

Therefore, y = 3(x + 3)(x - 2)