Raymond B. answered • 10/13/22
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P(1K) = 4/52 = 1/13
P(2ndK) = 3/51= 1/17
P(2 Kings) = 1/13 x 1/17 =1/(13)(17) = 1/221
Mos W.
asked • 10/13/22hard probability question
find the probability of selecting two kings when two cards are drawn without replacement from a standard deck of cards.
1/676
1/221
3/676
3/221
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