Edward C. answered 03/18/15
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Caltech Grad for math tutoring: Algebra through Calculus
Let L = length of rectangle
Let W = width of rectangle
Perimeter = 1200 feet = 2*L + 2*W ==> L = 600 - W
Area = L*W = (600 - W) * W = -W^2 + 600W
To maximize the area take the derivatives of the area function with respect to W
A' = -2*W + 600
A'' = -2 which is negative so any critical point will be a maximum
Set A' = 0 ==> -2*W + 600 = 0
-2*W = -600
W = 300
So L = 600 - 300 = 300
The field with the largest area has dimensions 300 ft by 300 ft