The equation m^2x^2 - (m+n)x + n =0 has two equal real roots.show that n^2 + 2(m-2m^2)n + m^2 = 0. If n is real, find the range of values of m

Question

find the range of values of m

I solved upto 16m3(m-1)>=0

which makes m >=0 or m>=1

but the ans is m<0 or m>=1

can u pls help

Answer 1

16m³(m - 1) ≥ 0

You soved for the = only

16m³(m - 1) > 0, tne

either

m³ Is positive making m > 0

and

m - 1 > 0 making m > 1

or

m³ is negative making m < 0

and m - 1 < 0 making m < 1

m < 0 or m > 1