What is the equation of the line that passes through the point (6, -2), and is parallel to the equation y=-1/2x-4

Question

What is the equation of the line that passes through the point (6, -2), and is parallel to the equation y=-1/2x-4

Answer 1

-1/2= (y- -2)/(x-6)

y+2 = -x/2 +3

y = -x/2 +1 in slope intercept form

or

y = (-1/2)x +1 where the coefficient of the x term = slope when the equation is solved for y. constant term = y intercept = 1 = the point (0,1)

check the answer

plug in the point (6,-2) x=6, y=-2

-2 = (-1/2)(6) +1 = -3+1 =-2