Ajinkya J. answered 09/28/22
Helping students crack the Ivy league and ace B-schools
Find an nth-degree polynomial function with real coefficients satisfying the given conditions. If you are using a graphing utility, use it to graph the function and verify the real zeros and the given function value.
- n = 3 ; -4 and 7 + 2i are zeros; f(-1) = 204
Since f(x) has real coefficients 7+2i is a root, so is 7-2i
So, -4, 7+2i, and 7-2i are roots
Since f(x) has degree 3, there can't be more than 3 distinct roots.
f(x) = a(x+4)(x-7-2i)(x-7+2i)
f(x) = a(x+4)(x2-14x+53)
f(-1) = 204, so
204 = a(-1+4)(-12-14(-1)+53)
204 = a(+3)(1+14+53)
204/204 = a
1 = a
f(x) = 1(x+4)(x2-14x+53)
You can use your graphing calculator (or desmos) to verify the real zero at x = 2
I hope this helps you!