Algebra II question

Question

   f(x)= 6x-5 /9x+2

Evaluate: f(-a), -f(a), f(a+h)

f(x) = −4x² + 2x − 9

Evaluate: -f(a), f(a+h)

Answer 1

You didn't use parentheses but I'm guessing f(x) = (6x-5)/(9x+2)

Just like finding f(5) or f(2) means either plugging 5 or 2 in for "x", the same holds true for f(-a)

f(-a) = (6(-a)-5)/(9(-a)+2) = (-6a - 5)/(-9a + 2)

To find -f(a), first find f(a) and then take its negative: f(a) = (6a - 5)/(9a + 2) so -f(a) = -(6a -5)/(9a + 2) = (-6a + 5)/(9a + 2)

f(a+h) = (6(a+h)-5)/(9(a+h)+2) = (6a + 6h - 5)/(9a + 9h + 2)

Do the same for f(x) = −4x² + 2x − 9