This is a problem about elementary symmetric polynomials. If you expand out the expression (x-α)(x-β)(x-γ), you see that the x2 term is -(α+β+γ), the x term is αβ+αγ+βγ, and the constant term is -αβγ. Since you know the coefficients of your polynomial, you know that
α+β+γ=0
αβ+αγ+βγ=-4
αβγ=8
These expressions are called the elementary symmetric polynomials in three variables. The problem is now to write your expression in terms of these polynomials. I assume your final terms is meant to be (γ + 2)/(γ − 2), else the problem cannot be solved this way.
It is always possible to rewrite a symmetric polynomial in terms of these elementary symmetric polynomials. Your expression is not a polynomial, but we can rewrite it as a quotient of two polynomials by finding a common denominator.
[(α+2)(β-2)(γ-2) + (α-2)(β+2)(γ-2) + (α-2)(β-2)(γ+2)]/ ((α-2)(β-2)(γ-2))
Expanding out the numerator and denominator takes some doing, but you should eventually get
[3αβγ-2αβ-2αγ-2βγ-4α-4β-4γ+24] / [αβγ-2αβ-2αγ-2βγ+4α+4β+4γ-8]
Now you can find the elementary symmetric polynomials hidden here:
[3αβγ-2(αβ+αγ+βγ)-4(α+β+γ)+24] / [αβγ-2(αβ+αγ+βγ)+4(α+β+γ)-8]
Plug in the known values, and simplify
[3·8-2·(-4)-4·0+24]/[8-2(-4)+4·0-8]
[24+8+24] / [8+8-8]
56/8
7