Find polar coordinates of the point whose cartesian coordinates are given. (-2√3 , 2)

Question

Find polar coordinates of the point whose cartesian coordinates are given. (-2√3 , 2)

Answer 1

Answer 2

The point is -2√3 units away from the origin along the x axis, and 2 units away along the y axis.

Polar coordinates have the form (R,θ), where R=√(x²+y²)=√((-2√3)²+2²)=√16=4.

Meanwhile, θ=tan^-1(y/x)=tan^-1(2/-2√3)=-0.52 rad.

This is equivalent to -30º, or -π/3.

So your coordinates are (4,-π/3)