Orlando S. answered 08/31/22
Middle/High School Mathematics and Physics Tutor
Hi, Jenna!
The equation of the circle can be expressed in the following form: (x - a)2 + (y - b)2 = r2, where (a,b) is the center of the circle and r is the radius.
In this example, we are given the coordinates of the center of the circle and a point on the circle itself. We can start by plugging our center, (3, -2) into our general formula and simplifying:
(x - 3)2 + (y - (-2))2 = r2
(x - 3)2 + (y + 2)2 = r2
Next, we need to find the value of r, or the radius. To do so, we can use the fact that our point on the circle, (-3, 4), must satisfy our equation. Therefore, we can plug these values into the x and y in our equation to solve for r:
((-3) - 3)2 + (4 + 2)2 = r2
(-6)2 + 62 = r2
36 + 36 = r2
r2 = 72
Now, of note, we could stop here if we wanted to. Our equation has a r2 in it, and not an r, so we could plug this into our equation for the circle to get our final answer:
(x - 3)2 + (y + 2)2 = 72
This is the equation of a circle with center (3, -2) and passing through the point (-3, 4)
If you needed to calculate the radius itself, you could do one extra step and take the square root of both sides of r2 = 72 to get r = 6√2 (the radius is always a positive value).
I hope this explanation was helpful, and please don't hesitate to reach out if you have any further questions!