Write an equation of circle .write your answer in standard form and then general form. The point lies on circle is (-3, 2).center of circle is the point (0 ,0)

Question

Write an equation of circle .write your answer in standard form and then general form. The point lies on circle is (-3, 2).center of circle is the point (0 ,0)

Answer 1

Here are the steps:

Equation of a circle: (x - h)² + (y - k)² = r² Center is at (h,k), r is radius.

If center is at (0,0) then h and k = 0

How to find r if point (-3,2) is on the circle? If center is at the origin (0,0) then there's a right triangle formed with r as the hypotenuse and two sides of length 2 and 3 (try to sketch it). So r² = 2² + 3² = 13

Equation is (x - 0)² + (y - 0)² = 13 → x² + y² = 13 in standard form.

General form is the standard form expanded by multiplying out the squared terms, but in this case h and k = 0, so you'd get the same result.

Answer 2

x^2 + y^2 = 13