
Marina M. answered 08/29/22
3+ Years of Teaching Experience in Algebra and Precalculus
From the above answer (from Raymond B.) you have the quadratic function for the Area:
A(w) = 1756w - 2w2
His solution uses derivatives. If you're not familiar with the derivatives, here is another solution.
After slight rearrangement we have
A(w) = -2w2 + 1756w
This is a parabola, opening down since the coefficient to w2 is negative (-2). It means that the vertex of this parabola is the maximum of the function, and this is exactly what we need.
The x-coordinate of the vertex (in our case it's w-variable) is:
w = -1756 / (2 x (-2)) = 1756 / 4 = 439 <--- this is the Width
And the Length = 1756 - 2w = 878
We can find the area in two ways:
- Width by Length = 439 x 878 = 385442 or
- A(439) = -2w2 + 1756w2 = -2 x (439)2 + 1756 x 439 = 385442
Hope this helps