A rectangle has a length that is one more than twice thw width. If the perimeter of the rectangle is 42 inches, how wide is the rectangle?

Answer 1

L=1+2W

Perimeter = 2L +2W = 2+4W+2W = 6W+2 =42

6W =42-2=40

W =40/6 = 6 2/3 inches Wide

L=1+2(6 2/3) =14 1/3

L+W = 14 2/3 +6 2/3 = 21

2L+2W = 42 inches = Perimeter

Answer 2

L = 2W + 1

P = 2W + 2L

42 = 2W + 2(2W + 1)

42 = 2W + 4W + 2

Combine like terms on opposite sides of the equation and solve for W.

To check answer, substitute value for W in equation for L to get L, See if perimeter is 42.

Hint: Answers are not integers.