Find all the zeros of the function f(x) = x3 + 22x2 + 160x + 400

Question

Similar issue as my previous post, it's asking for the finding zeros of the function, answered it as x=-10, it was correct to a point, because there is more than one answer I guess.

Answer 1

This is a polynomial of the third degree so it has to have three roots, real and/or complex

It factors to (x+10)(x²+12x+40)=0

The first root is -10

We can use quadratic formula on the second () to find the remaining roots that are 6+2i and 6-2i

Answer 2

(x + 10)(x² + 12x + 40)