A metallurgist has one alloy containing 21% copper and another containing 36% copper. How many pounds of each alloy must he use to make 44 pounds of a third alloy containing 33% copper?

Answer 1

Let x = number of pounds of 21% copper alloy. Then 44 - x = number of pounds of 35% copper alloy.

21x + 36(44 - x) = 33(44)

Solve for x.