algebra q example

Question

What are the zeros of this cubic function. please show me the steps

Answer 1

The zeroes of the cubic function f(x)=(x-3)(x-1)(x+2) are 3, 1, and -2.

This equation is in factored form, so it will be easy to find the zeroes. The zeroes in factored form are the "a" in a term (x-a). Thus, 3, 1 and -2 are the zeroes. To check, plug any one of those back into the equation.

at x=3, f(x)=(3-3)(3-1)(3+2)=(0)(2)(5)=0

at x=1, f(x)=(1-3)(1-1)(1+2)=(-2)(0)(3)=0

at x=-2, f(x)=(-2-3)(-2-1)(-2+2)=(-5)(-3)(0)=0