Find the first five terms

Question

F(1)=2/3,f(n)=f(n-1)*3/2 for n≥2

Answer 1

F(1)=2/3,f(n)=f(n-1)*3/2 for n≥2

# F(1)=2/3

# F(2) = f(2-1) * 3/2 = 2/3 * 3/2 = 6/6 = 1

# F(3) = f(3-1) * 3/2 = 1 * 3/2 = 3/2

# F(4) = f(4-1) * 3/2 = 3/2 * 3/2 = 9/4

# F(5) = f(5-1) * 3/2 = 9/4 * 3/2 = 27/8

Not really sure if you need the 6th term but if you do then, you can follow the pattern and figure out the answer.

I hope this helps :)

Answer 2

f(1) = 2/3

f(n) = f(n-1)^(3/2) for n>1

f(2) = f((1)(3/2) = (2/3)(3/2) = 1

f(3) = f(2)(3/2) = 1(3/2) = 3/2

f(4) = f(3)(3/2) (3/2)(3/2) = 9/4

f(5) = f(4)(3/2) = (9/4)(3/2) = 27/8

2/3, 1, 3/2, 9/4, 27/8, ...