Determine the equation of the parabola that opens to the left, has vertex (2,8) and a focal diameter of 28? (Written in (y-k)^2 = +-4p(x-h) form)

Answer 1

This is basically just a plug in problem using the vertex form of the equation.

h = 2, k = 8 and 4p = -28. Note that 4p is negative when the parabola opens to the left -- as is the case here -- or downward.

(y - 8)^2 = -28(x - 2)