Write the equation of a line that includes the point (1, 5) and has a slope of 3 in slope-intercept form.

Answer 1

The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.

We know that the graph goes through (1,5) and the slope is 3, so we have 3 of the 4 unknowns and can solve for b: 5 = 3(1) + b, so b = 5 - 3 = 2

Then the equation for the line is y = 3x + 2. You can use the Desmos Graphing Calculator website to check it.

Answer 2

When you have a slope and a pt you can use this:

(y - y₁ ) = m(x - x₁) -- where (x₁ , y₁) corresponds to (1, 5) and m is the slope.

Then you can make y the subject to put it in standard form. Making y the subject just means solving for y, or getting y by itself.