Al Y. answered 05/17/22
Data Scientist with several years in Business data analysis
In theory yes!
If µ(n) = ∑n1 (xn) /n is the average for the first n terms, then µ(n+1) = ( xn+1 /(n+1) ) + n µ(n) /(n+1).
So by storing previous n-term average and n+1-th term xn+1 you may calculate n+1-th average µ(n+1).