a=9400+b => b=a-9400
c=b-8800 => c=(a-9400) - 8800 = a-18200
a+b+c=212100 => a+(a-9400)+(a-18200)=212100 => 3a - 9400 - 18200 = 212100
3a = 239700 => a=79900
b = 79900-9400=70500
c= 70500-8800 = 61700
Nae L.
asked 05/14/22Stadium A seats approximately
9400
more fans than does stadium B. Stadium C seats
8800
fewer fans than stadium B. If the total seats in these three stadiums is
212,100,
how many seats are in each of the three stadiums?
The number of seats in stadium A is
stadium B is
,
stadium C is
a=9400+b => b=a-9400
c=b-8800 => c=(a-9400) - 8800 = a-18200
a+b+c=212100 => a+(a-9400)+(a-18200)=212100 => 3a - 9400 - 18200 = 212100
3a = 239700 => a=79900
b = 79900-9400=70500
c= 70500-8800 = 61700
Richard C. answered 05/14/22
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