Inactive Tutor answered 05/12/22
h(t) = -16t^2 + 312t + 9
it hits ground when h=0
-16t^2 +312t + 9 = 0
t = 312/32 + (1/32)sqr(312^2 + 4(16)(9))
t = 19.53 seconds
= 19.5 seconds rounded off to nearest tenth of a second to hit the ground
Mike H.
asked 05/12/22You fire a rocket straight up with an initial velocity of 312 ft/sec that is on a 9ft platform. To the nearest tenth of a second when does the rocket land
pls show work thank you :)
Inactive Tutor answered 05/12/22
h(t) = -16t^2 + 312t + 9
it hits ground when h=0
-16t^2 +312t + 9 = 0
t = 312/32 + (1/32)sqr(312^2 + 4(16)(9))
t = 19.53 seconds
= 19.5 seconds rounded off to nearest tenth of a second to hit the ground
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Mike H.
Thank you so much I appreciate it :D05/12/22