law of sines solving a triangle

Question

Using the Law of Sines to solve the all possible triangles if If no answer exists, enter DNE for all answers.

∠B is_____degrees

∠C is_____degrees;

c=

Assume ∠ A is opposite side a , ∠ B is opposite side b , and ∠ C is opposite side c .

Answer 1

SinB/b = SinA/a

SinB = bSinA/a = 15Sin104/35 = (3/7)Sin104 = 3(7).9703 = .416

B = 24.57 degrees

C = 180-104-24.57 = 51.43 degrees

c/SinC = 35/Sin104

c = 35Sin51.43/9703 = about 28.2

A,B,C are 104, 24.6, 51.4 degrees with opposite sides a, b, c = 35, 15, 28.2

just one triangle