$9000 invested at an APR of ​8% for 2 years.

Answer 1

after one year the investment has grown to $9720.00

after two years it's 9072(1.08) = $10,497.60

A=P(1+r)^t where r = APR and y= number of year

A=9000(1.08)^2= 10,497.6

assuming annual compounding

if it's continuous compounding the formula is A=Pe^rt

if it's compounded n times per year the formula is A=P(1+r/n)^nt