What is the equation of the line perpendicular to y=2x+6 and passing through (4,5)?

Answer 1

a line perpendicular to y=2x+6 passing through (4,5)

is y -5 = (-1/2)(x-4) in point slope form

y = -x/2 +7 in slope intercept forrm

or

x + 2y = 14 in standard form

or

x +2y -14 = 0 in general form

perpendicular lines have a negative inverse slope

slope of the given line is 2, the coefficient of the x term when the equation is solved for y

the negative inverse of 2 is -1/2