Peter R. answered 04/28/22
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
1st leg: 10 mi/4 hrs = 2.5 mph avg.
2nd leg: (26 - 10) mi/(12 - 4) hrs = 16/8 = 2 mph avg.
O'all trip: 26mi/12 hrs = 2.17 mph avg.
Mary C.
asked 04/27/22Peter R. answered 04/28/22
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
1st leg: 10 mi/4 hrs = 2.5 mph avg.
2nd leg: (26 - 10) mi/(12 - 4) hrs = 16/8 = 2 mph avg.
O'all trip: 26mi/12 hrs = 2.17 mph avg.
Mark M. answered 04/27/22
Mathematics Teacher - NCLB Highly Qualified
mph = d / t
mph = (26 - 10) / (12 - 4)
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