An atom of gold has a mass of approximately 3.25 x 10^22 grams . What is the mass of 9000 atoms of gold

Answer 1

9,000 = 9 x 10^3

9,000 x 3.25 x 10^22

=9 x 10^3 x 3.25 x 10^22

=9x3.25 x 10^3 x 10^22

= 29.25 x 10^(3+22)

= 29.25 x 10^25

= 2.925 x 10^26 grams for 9,000 atoms