please help! got tunnel vision on this one

Question

The amount of horsepower needed to overcome a wind drag on a certain automobile is given by: h(s) = 0.005s² +.007s - 0.031, where S is the speed of the car in miles per hour.

How much horsepower is needed to overcome the wind drag on this car if it is traveling 55 miles per hour?

(Hint: Round to the nearest hundredth)

By completing the square, at what speed will the car need to use 225 horsepower to overcome the wind drag? (Hint: Leave in fraction form until the end, and then round to the nearest hundred)

Answer 1

a) .005(55)² + .007(55) -.031 =

b) .005s² +.007s - .031 = 225 or s² + 7/5 s - 225.031/.005 = 0

(s + 7/10)² - (7/10)² - 225.031/.005 = 0

s + 7/10 = sqrt(45006.69) and solve for s.

This equation is very strange as the constant term is not of the right magnitude to make a difference.

Answer 2

h(25) = 0.005(25)² +.007(25) - 0.031

h(s) = 0.005s² +.007s - 0.031

h(s) = 0.005(s² + 0.007s/(0.005 )(2) + 0.007s/(0.005 )(2)) - 0.031 - 0.007s/(0.005 )(2)