Find the 25th term of this arithmetic sequence: 132, 136, 140, 144,...

Answer 1

a₁ = 132

d = 4

n = 25

a_n = a₁ + (n - 1)d The formula!

Can you substitute values and answer?

Answer 2

First, find the equation that would make the sequence. (y=mx+b)

1) find the difference of the sequence terms

136-132 = 4

2) y=4x

check y=4(1) does not equal132 out first number

3) y=4x+128 + or - to make it work

check again y=4(2)+128 works!

That was for the first, and second number...

Second, to find the 25th term substitute 25 into the equation and solve.