Find the first 5 terms of the sequence that follows the rule: 3n+7

Answer 1

The first five terms of the sequence are the result of the rule when you substitute 1,2,3,4 and 5 into the rule for n

Answer 2

an = 3n+7

a1 = 3(1) +7 = 10

a2 = 3(2)+7 = 13

a3 = 3(3) +7 = 16

a4 = 3(4) + 7 = 19

a5 = 3(5) + 7 = 22

sequence is arithmetic with a common difference of d=3

the nth term = the 1st term plus the common difference times n-1

an = a1 + d(n-1)

an = 10 +3(n-1)

a1 = 10 +3(1-1) = 10

a2 = 10 + 3(2-1) = 13

a3 = 10 +3(3-1) = 16

a4 = 10+ 3(4-1) = 19

a5 = 10+3(5-1) = 22