Charlsey H.

asked • 03/13/22

Find the area of a triangle bounded by the y -axis, the line   f(x)=10-2    , and the line perpendicular to  that passes through the origin. 

Find the area of a triangle bounded by the y-axis, the line  f(x)=10-2  , and the line perpendicular to  that passes through the origin. 


Doug C.

Is that supposed to be the line "f(x)" = 10x -2"? Something else?
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03/13/22

Stanton D.

But Charlsey H. sayeth naught. f(x) = x^10-2; f(x) = 10^(-2x); f(x) = 10-2^x, and they just get weirder from there! But while we're on the subject, what's the polynomial function for the maximum number of regions into which a plane may be divided by n lines in the plane?
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03/14/22

Brenda D.

tutor
Charlsey H please clarify f(x) so we can try to help you. There is a lot of help available as you can see from the comments above.
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03/14/22

1 Expert Answer

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Luis G. answered • 03/22/22

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Draw a picture. You have a right triangle whose legs meet at the center. The hypotenuse is given by y=10-2x. A height and base is needed to compute the area. The height will be formed when the line y=10-2x intersects the y-axis and the base when y=10-2x intersects the x-axis. The y and x-interceptes are (0,10) and (5,0) respectively. Therefore, the area equals 1/2(10)(5) = 25 using the formula A=1/2bh.

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