Raymond B. answered 03/10/22
Math, microeconomics or criminal justice
initial population = 1,000
it doubles in 10 years to 2,000
in 10 more years it doubles again to 4,000. that's 20 years total
then 10 more years, it's 8,000, for 30 years total
10 more, & it's 16,000 for 40 years total
10 more, it's 32,000 for 50 years total
but the natural annual growth rate would be r in an exponential function, where t= number of years and e= approximately 2.71828
doubling time means 10 in the following equation
2 = e^10r
take natural logs of both sides to get
ln2 =10r
r =ln2/10 = .0693 = 6.93 % annual growth rate
32=(1)e^.0693t where t = number of years until 1 thousand reaches 32 thousand
ln32 = .0693t
t =ln32/.0693 = 50 years to reach 32,000 population
General formula is A=Pe^rt. P is the starting amount, A the ending amount, r=annual growth rate, t= years