Paris J.

asked • 02/28/22

Solve the system for each variable, and check your solutions.

11. x + 5y + 10z = 47 and y = z and x + y + z = 8

12. x + y + z = 6 and 2x – y + z = 3 and x + 2y – 3z = -4

13. x + y + z = 12 and x + 2y + 3z = 31 and 9y + z = 1


Brenda D.

tutor
In number 11 since y=z you can make a substitution. Once you make the substitution you will have two in equations in two variables. As with two equations in two unknowns there are several ways to work on your problems, graphing, substitution, elimination. For three equations in three unknowns, a Matrix (or Matrices) can also be used. In looking at your other related questions it appears that you may not be using Matrices, if you are please let us know so we can help you. If you are not using Matrices, elimination and substitution will certainly work for your problems.
Report

02/28/22

1 Expert Answer

By:

Aricia P. answered • 02/28/22

Tutor
2.8 (12)

I specialize in Algebra, Geometry, Algebra 2, Trigonometry, Stat

See tutors like this
See tutors like this

11. X+5y+10z = 47.

Y=z meaning

X+y+z= 8

Take x+y+z=8

But y=z meaning

X+y+y=8

X+2y=8 equation ( 1)

X+5y+10y=47 (2) equation

Solve the together

X+2y=8

X+15y=47

Eliminate x we have 2y-15y= 8-47

_13y= -39

Therefore y= 3

Taking x +15y= 47

X +15(3)=47

X+45=47

Therefore x=2.

But x+y+z= 8

2+3+z=8

5+z= 8

Z=8-5

Z=3

Upvote • 0 Downvote
More
Report

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.